| 1 |
% |
| 2 |
% I = intbet2outcrops(TRACER,LIMITS,LAT,LONG) |
| 3 |
% |
| 4 |
% This function computes the horizontal surface integral between two |
| 5 |
% outcrops of the TRACER field, given fixed limits eastward, westward |
| 6 |
% and southward. |
| 7 |
% |
| 8 |
% TRACER = TRACER(LAT,LONG) : surface tracer variable in 2D |
| 9 |
% LIMITS = [OUTCROP1 OUTCROP2 MAX_LAT1 MAX_LAT2 MAX_LONG1 MAX_LONG2] |
| 10 |
% : limit's values (MAX_LAT2 is used only if |
| 11 |
% the outcrop's surfaces reach them). |
| 12 |
% LAT : latitude axis (1D), degrees northward |
| 13 |
% LONG : longitude axis (1D), degrees east |
| 14 |
% I : single surface integral value |
| 15 |
% |
| 16 |
% 06/15/2006 |
| 17 |
% gmaze@mit.edu |
| 18 |
% |
| 19 |
|
| 20 |
|
| 21 |
function varargout = intbet2outcrops(TRACER,LIMITS,LAT,LONG) |
| 22 |
|
| 23 |
|
| 24 |
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% |
| 25 |
% PRE-PROCESS and ERROR CHECK % |
| 26 |
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% |
| 27 |
|
| 28 |
% Check number of input: |
| 29 |
if nargin ~= 4 |
| 30 |
help intbet2outcrops.m |
| 31 |
error('intbet2outcrops.m : Wrong number of parameters') |
| 32 |
return |
| 33 |
end %if |
| 34 |
|
| 35 |
% Check dimensions: |
| 36 |
n = size(TRACER); |
| 37 |
if length(n)==2 |
| 38 |
[ny nx] = size(TRACER); |
| 39 |
if ny~=length(LAT) | nx~=length(LONG) |
| 40 |
help intbet2outcrops.m |
| 41 |
error('intbet2outcrops.m : Axis must have same dimensions than TRACER field'); |
| 42 |
return |
| 43 |
end %if |
| 44 |
else |
| 45 |
help intbet2outcrops.m |
| 46 |
error('intbet2outcrops.m : TRACER must be a 2D field') |
| 47 |
return |
| 48 |
end %if |
| 49 |
|
| 50 |
% Ensure that axis are of dim: (1,N) and well sorted (increasing values): |
| 51 |
a=size(LAT); |
| 52 |
if a(1) ~= 1, LAT=LAT'; end |
| 53 |
S = sort(LAT); |
| 54 |
if S ~= LAT |
| 55 |
help intbet2outcrops.m |
| 56 |
error('intbet2outcrops.m : LAT must be increasing values') |
| 57 |
return |
| 58 |
end %if |
| 59 |
a=size(LONG); |
| 60 |
if a(1) ~= 1, LONG=LONG'; end |
| 61 |
S = sort(LONG); |
| 62 |
if S ~= LONG |
| 63 |
help intbet2outcrops.m |
| 64 |
error('intbet2outcrops.m : LONG must be increasing values') |
| 65 |
return |
| 66 |
end %if |
| 67 |
|
| 68 |
% LIMITS definition: |
| 69 |
if length(LIMITS) ~= 6 |
| 70 |
help intbet2outcrops.m |
| 71 |
error('intbet2outcrops.m : LIMITS must contains 6 values') |
| 72 |
return |
| 73 |
end %if |
| 74 |
OUTCROPS = sort( LIMITS(1:2) ); |
| 75 |
LAT_MAX = sort( LIMITS(3:4) ); |
| 76 |
LONG_MAX = sort( LIMITS(5:6) ); |
| 77 |
|
| 78 |
|
| 79 |
|
| 80 |
%%%%%%%%%%%%%%%%%%%% |
| 81 |
% COMPUTE INTEGRAL % |
| 82 |
%%%%%%%%%%%%%%%%%%%% |
| 83 |
% We first determine the element surface matrix and points to integrate: |
| 84 |
[I1 I1mat dI1] = subfct_getsurf(TRACER,LAT,LONG,[OUTCROPS(1) LAT_MAX LONG_MAX]); |
| 85 |
[I2 I2mat dI2] = subfct_getsurf(TRACER,LAT,LONG,[OUTCROPS(2) LAT_MAX LONG_MAX]); |
| 86 |
|
| 87 |
% Then we determine the outcrop surface limits: |
| 88 |
I1mat(find(I1mat==0))=NaN; |
| 89 |
I2mat(find(I2mat==0))=NaN; |
| 90 |
I1mat(find(I1mat==1))=0; |
| 91 |
I2mat(find(I2mat==1))=0; |
| 92 |
Imat = I1mat + I2mat; |
| 93 |
Imat(find(Imat==0))=1; |
| 94 |
Imat(isnan(Imat))=0; |
| 95 |
Imat = logical(Imat); |
| 96 |
|
| 97 |
% And the integral of the TRACER on it: |
| 98 |
I = sum(TRACER(Imat).*dI1(Imat)); |
| 99 |
|
| 100 |
|
| 101 |
|
| 102 |
|
| 103 |
%%%%%%%%%%% |
| 104 |
% OUTPUTS % |
| 105 |
%%%%%%%%%%% |
| 106 |
switch nargout |
| 107 |
case 1 |
| 108 |
varargout(1) = {I}; |
| 109 |
case 2 |
| 110 |
varargout(1) = {I}; |
| 111 |
varargout(2) = {Imat}; |
| 112 |
case 3 |
| 113 |
varargout(1) = {I}; |
| 114 |
varargout(2) = {Imat}; |
| 115 |
varargout(3) = {dI1}; |
| 116 |
end %switch nargout |
| 117 |
|
| 118 |
|
| 119 |
|
Parent Directory
| 
Revision Log
| 
Revision Graph